| Assignment or WS# | Page | Answers or Problem # Corrected |
|---|---|---|
| NOTATION | I would not normally use slant fractions; however, it is the only way I know to do it in this mode. This could create confusion or a wrong answer if I did not use parentheses when multiplying a slant fraction by another factor. I would expect your answers to use "straight over" fractions and not have these extra parentheses (as in #70 in the first set of answers.) | |
| WORKSHEET CORRECTIONS | When Worksheets must be corrected, I will try to upload the corrected version as soon as possible. If you have not printed out the incorrect version, it will not affect you. However, if you have already printed the first version and do not want to reprint, I will put the problem numbers that have been corrected so that you can make the needed changes on your copy by going to the corrected version. | |
| T1 | 38 | #64. n+4 #66. n-7 #68. 75-n #70. (1/3)n #72. 3n+7 #74. 50/n #76. (1/3)n+6 #78. 12(n+7) #80. n-5 #82. 65-x #84. 98/n #86. c/4 #88. 5n+10d+25q #90. n+1 #92. n+2 #94. d/12 #96. i/12 #98. 0.1d or d/10 |
| WS#2 | Problems 10, 51, & 56 have been corrected. | |
| WS#3 | Problems 94, 95, & 96 have been corrected. | |
| 2.1B | 52 | #52. If x = the number, the equation is 7x-1=31+3x. Solution is x=8.
#54. If x = the 1st integer, then x+1 is the 2nd, etc. The equation is x + (x+1) + (x+2) + (x+3) = -118. (Parenteheses are not necessary.) The solution is x = -31, so the 4 integers are -31, -30 -29, -28. #56. If x = the 1st even integer, then x+2 and x+4 are the other two integers. The equation is 4x - (x+4) = 6 + 2(x+2). (Parentheses ARE necessary.) The solution is x = 14, so the 3 consecutive even integers are: 14, 16, 18. |
| 2.2B | 60 | #42. If x = the number, the equation is
(1/2)x + (3/4)x = 2 + (4/3)x. (See NOTATION above on slant fractions.) The solution is x = -24. |
| 7.1 Extra Problems | 346 & Class | #1. (10,-3); (-4,4) #2. (-1,8); (-3,12) #3. (5,8); (-1,-3)
#4. (-2,-9); (3,6)
#5. (4,-3); (6,-6) #6. (-3,4); (12,-6) #7. (2,-5/2); (-4,-10) #8. (3,8); (-9/2,-2) #9. (6,-3); (14,-5) #10. (-2,10); (2,-12) |
| WS#7 | Answer to #23 has been corrected. | |
| 2.1C | 52 | #58. Let x be the smaller and y be the larger number, then x+y=103 and
y=1+5x. The solution is x=17 and y=86
#60. Let x be the hourly rate charged. 25+5x=130. The solution is x=$21. #62. Let N, D and Q be the number of nickels, dimes, and quarters. N+D+Q=122; D=3+4N; Q=D-19. The solution is: N=15; D=63; Q=44. #64. Let F and M be the number of females and males. F+M=62; F=2M-1. The solution is F=41; M=21. #66. Let x be the number of bicycles he sells. 300+15x=750. The solution is x=30. |
| 2.2C | 60 | #48. Let D, Q and S be the number of dimes, quarters and Silver dollars.
D+Q+S=116; Q=(3/4)D-5; S=7+(5/8)D. The solution is D=48; Q=31; S=37
#50. Let x be Annilee's present age and y be Jessie's present age. x=(2/3)y; (x+12)+(y+12)=54. The solution is x=12; y=18. #52. Let x be Ian's present age and y be his brother's present age. x+y=45; x+5=(5/6)(y+5). The solution is x=20; y=25 #54. Let T, M, and A be the salaries for Tim, Maida and Aaron. (1/3)(T+M+A)=24,000; M=T+10,000; A=2000+2T. The solution is T=$15,000; M=$25,000; A=$32,000 |
| 2.2D | 60 | #44. Let W and L be the width and length of the rectangle.
W=(2/3)L-3; 2W+2L=114. The solution is W=21cm; L=36cm.
#56. Let x be the measure of the angle, C its complement, and S its supplement. x+C=90; x+S=180; (1/2)C+(3/4)S=110. The solution is x=56 degrees. (We were not asked for the other 2) #58. A+B+C=180; B=(1/2)A-8; C=28+A. The solution is A=64; B=24; C=92. |
| 2.4D | 78 | #48. Let F, S and T be the lengths of the first, second and third sides of the triangle. F+S+T=42; S=1+2F; T=3F-1. The solution is F=7in S=15in; T=20in. |
| 2.3B | 68 | #30. $32 #32. $46.80 #34. $4.25 #36. $0.80 #38. 85%
#40. 25%
#42. $14,900 #44. $1000 @ 8%; $3000 @ 9% #46. $2350 #48. 15 nickels; 25 dimes; 50 quarters #50. 12 dimes; 25 quarters |
| 2.4F | 79 | #58. 10 gal. #60. 20/9 cups #62. 16/5 qts |